Timeline for Perfect quotients of braid groups
Current License: CC BY-SA 4.0
14 events
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| Jun 30, 2023 at 2:03 | history | edited | Ian Gershon Teixeira | CC BY-SA 4.0 |
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| Jun 28, 2023 at 9:06 | history | edited | Ian Gershon Teixeira | CC BY-SA 4.0 |
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| Jun 28, 2023 at 8:45 | history | edited | Ian Gershon Teixeira | CC BY-SA 4.0 |
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| Jun 28, 2023 at 8:26 | history | edited | Ian Gershon Teixeira | CC BY-SA 4.0 |
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| Jun 28, 2023 at 5:58 | vote | accept | Ian Gershon Teixeira | ||
| Jun 24, 2023 at 10:22 | comment | added | Ian Agol | One ought to be able to prove this for most braid groups in a similar way to $B_3$. It was shown by Venkataramana that Burau representations of braid groups are arithmetic in the appropriate range. Arithmetic groups should have lots of congruence quotients which are perfect by the strong approximation theorem. But I don’t have quite enough knowledge of the appropriate group theory to complete this line of argument. doi.org/10.4007/annals.2014.179.3.4 | |
| Jun 24, 2023 at 9:20 | answer | added | Ian Agol | timeline score: 4 | |
| Jun 23, 2023 at 11:35 | comment | added | Ian Gershon Teixeira | Ok I clarified that I want infinitely many non-isomorphic (preferably finite) perfect quotients | |
| Jun 23, 2023 at 11:31 | history | edited | Ian Gershon Teixeira | CC BY-SA 4.0 |
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| Jun 23, 2023 at 11:22 | comment | added | YCor | "infinitely many quotients": do you mean infinitely many normal subgroups, or infinitely many non-isomorphic quotients? (However for these group one expects continuum many quotients, although asking for unbounded cardinal finite perfect quotients is reasonable too.) | |
| Jun 23, 2023 at 11:20 | history | edited | YCor | CC BY-SA 4.0 |
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| Jun 23, 2023 at 8:48 | history | became hot network question | |||
| Jun 23, 2023 at 4:22 | answer | added | AGenevois | timeline score: 10 | |
| Jun 23, 2023 at 0:43 | history | asked | Ian Gershon Teixeira | CC BY-SA 4.0 |