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Jun 22, 2023 at 11:02 comment added Itay Great! Thank you very much!
Jun 22, 2023 at 11:02 vote accept Itay
Jun 22, 2023 at 7:57 comment added Fedor Petrov fixed this too, please check
Jun 22, 2023 at 7:54 history edited Fedor Petrov CC BY-SA 4.0
added 69 characters in body
Jun 22, 2023 at 7:14 comment added Itay Thank you Professor. However, if I am not mistaken, $\alpha=\mathbb{E} \langle u,w\rangle\cdot \langle v,w\rangle$ is still missing the square. Can we still introduce $w$ to the corrected $\alpha=\mathbb{E} {u_1}^2 {v_1}^2$ like the current answer does?
Jun 22, 2023 at 6:58 comment added Fedor Petrov certainly, fixed this
Jun 22, 2023 at 6:58 history edited Fedor Petrov CC BY-SA 4.0
added 650 characters in body
Jun 22, 2023 at 6:05 history answered Fedor Petrov CC BY-SA 4.0