Timeline for Continuous up to the boundary without boundary smoothness
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 19, 2023 at 2:40 | comment | added | sorrymaker | @Giorgio Metafune, yes, $u$ must be bounded globally in $\Omega$. | |
| Jun 19, 2023 at 2:37 | vote | accept | sorrymaker | ||
| Jun 19, 2023 at 1:38 | answer | added | user378654 | timeline score: 4 | |
| Jun 18, 2023 at 18:37 | comment | added | Giorgio Metafune | @user378654 But such a function is continuous up to the boundary, even though it doen not vanish at 0 | |
| Jun 18, 2023 at 18:16 | comment | added | user378654 | A standard counterexample is $\Omega = B_1 \setminus \{0\}$ and say $u = 1 - |x|^2$. | |
| Jun 18, 2023 at 15:45 | comment | added | Giorgio Metafune | I am also not sure about the result but the $L^\infty$ bound seems to be global in $\Omega$, not only local. Do you agree? | |
| Jun 18, 2023 at 5:28 | history | edited | sorrymaker | CC BY-SA 4.0 |
added 11 characters in body; edited title
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| Jun 18, 2023 at 5:21 | history | asked | sorrymaker | CC BY-SA 4.0 |