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Jan 23 at 18:07 answer added Sylvain JULIEN timeline score: -1
Nov 13, 2023 at 14:29 comment added Michael Lugo Relevant OEIS sequence: oeis.org/A047160, "a(n) = smallest number m >= 0 such that n-m and n+m are both primes" - I was hoping for a pointer into the literature, but nothing there.
Nov 13, 2023 at 10:04 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jul 16, 2023 at 12:12 comment added Gerry Myerson I think there has been more (computational) work on how to make $p-q$ as big as possible, than as small as possible.
Jul 16, 2023 at 11:08 comment added David E Speyer If you look at the ternary Goldbach problem, it is known that every sufficiently large odd number can be written as $p_1+p_2+p_3$ with $p_i = n/3 + O(n^{11/20+\epsilon})$. arxiv.org/abs/1610.02017
Jul 16, 2023 at 10:03 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jun 16, 2023 at 9:15 answer added TravorLZH timeline score: 1
Jun 12, 2023 at 10:03 comment added Wojowu Almost certainly there are no actually proven results in this direction. But one can ask for heuristics, or about what is known for most numbers (since we know Goldbach holds for most even numbers, I imagine results of this sort might be available).
Jun 12, 2023 at 9:38 comment added Geoffrey Irving As a first heuristic, if we start at $p = q = n$ and walk outwards, the expected time to hit primes would be $O(\log^2 n)$. So an upper bound is probably that plus another $\log \log n$ factor?
Jun 12, 2023 at 8:37 history asked P.-S. Park CC BY-SA 4.0