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David Roberts
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Converted from (now-deleted) a comment by Christian Remling:

This is false: $$ A=\begin{pmatrix} 0 & 0\\ 0& 1\end{pmatrix},\quad B=\begin{pmatrix} 0 & 1\\ 1 & 0\end{pmatrix}$$ Then $A+\epsilon B$ is not positive definite for any $\epsilon\not= 0$.

Converted from a comment:

This is false: $$ A=\begin{pmatrix} 0 & 0\\ 0& 1\end{pmatrix},\quad B=\begin{pmatrix} 0 & 1\\ 1 & 0\end{pmatrix}$$ Then $A+\epsilon B$ is not positive definite for any $\epsilon\not= 0$.

Converted from (now-deleted) a comment by Christian Remling:

This is false: $$ A=\begin{pmatrix} 0 & 0\\ 0& 1\end{pmatrix},\quad B=\begin{pmatrix} 0 & 1\\ 1 & 0\end{pmatrix}$$ Then $A+\epsilon B$ is not positive definite for any $\epsilon\not= 0$.

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Federico Poloni
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Converted from a comment:

This is false: $$ A=\begin{pmatrix} 0 & 0\\ 0& 1\end{pmatrix},\quad B=\begin{pmatrix} 0 & 1\\ 1 & 0\end{pmatrix}$$ Then $A+\epsilon B$ is not positive definite for any $\epsilon\not= 0$.