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Jun 5, 2023 at 16:42 vote accept Analyst
Jun 5, 2023 at 16:42 comment added Medo Also, $\lambda$defined this way depends on $t_{1}$ and $t_{2}$. So, it does not make sense to let $C_{1}$ or $C_{2}$ depend on $\lambda$.
Jun 5, 2023 at 16:17 answer added Iosif Pinelis timeline score: 6
Jun 5, 2023 at 16:10 comment added Aleksei Kulikov If I didn't make mistake, taking $x = 0$, $t_2 = 2t_1$ and sending $t_1$ to zero gives a counterexample.
Jun 5, 2023 at 16:02 history edited Daniele Tampieri CC BY-SA 4.0
Spacing.
Jun 5, 2023 at 15:51 history edited Analyst CC BY-SA 4.0
deleted 22 characters in body
Jun 5, 2023 at 15:46 history asked Analyst CC BY-SA 4.0