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Jun 3, 2023 at 11:05 comment added Jjj Thanks! Well, then I guess (if i have done it correctly) that the maximum value is the dimension d? Doest it seem correct?
Jun 3, 2023 at 10:58 comment added Jochen Wengenroth $\sum_{j.k} x_j x_k =\left(\sum_k x_k\right)^2$ should help.
Jun 3, 2023 at 10:23 comment added Jjj I tried it now but cant manage to solve it using lagrange multipliers
Jun 2, 2023 at 15:07 comment added Jochen Wengenroth Did you try to maximize $\sum x_jx_k$ subject to $\sum x_j^2=1$?
Jun 2, 2023 at 11:29 comment added Jjj @JochenWengenroth Thanks, but maybe it is possible to get a linear dependence on $d$ instead of a quadratic one that I obtained above?
Jun 2, 2023 at 11:23 comment added Jochen Wengenroth For $r=1$ and $x=d^{-1/2}(1,1,\ldots,1)$ you have $\sum_{j,k=1}^d |x_jx_k|= d$. There does not seem to be reasonnable bound independent of the dimension.
S Jun 2, 2023 at 10:32 review First questions
Jun 2, 2023 at 10:58
S Jun 2, 2023 at 10:32 history asked Jjj CC BY-SA 4.0