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Jun 2, 2023 at 8:01 comment added user197402 Thank you for the very nice clarification :)
May 31, 2023 at 22:16 comment added R. van Dobben de Bruyn There is an alternative argument for projective varieties $Y$ for which every morphism $\mathbf P^1\to Y$ is constant (this includes subvarieties of abelian varieties). Indeed, consider the closure $\bar\Gamma$ of the graph $\Gamma_\phi\subseteq X\times Y$, which maps birationally onto $X$ via the first projection $p\colon\bar\Gamma\to X$. When $X$ is smooth, such a map has linearly connected fibres by a result of Murre, which (by assumption on $Y$) are contracted by the second projection $q\colon\bar\Gamma\to Y$. Then $q$ factors through $p$, i.e. $\phi$ is everywhere defined.
May 31, 2023 at 13:51 comment added user197402 Ok I see, this was definitely too optimistic. Thank you for the clarification!
May 31, 2023 at 13:45 comment added Jason Starr There is almost certainly no general argument that does not use Hironaka. Let $Z$ be an arbitrary (singular) projective variety with an embedding in $X=\mathbb{P}^n$. Let $X'$ be the blowing up of $X$ along $Z$, and let $X'\hookrightarrow \mathbb{P}^r$ be a closed immersion. For this rational transformation, $X\dashrightarrow Y$, a sequence of blowups with smooth centers that regularizes the transformation also implies a resolution of singularities of $Z$.
May 31, 2023 at 13:45 comment added user197402 Oh I see, yes I know the result on abelian varieties but I did not think about using it for the result, as abelian varieties are a bit too special. Thank you both very much!
May 31, 2023 at 13:42 comment added Jason Starr It also extends to N'eron models of Abelian varieties (it is roughly the defining property of a N'eron model). Sometimes it is called "Weil extension."
May 31, 2023 at 13:13 comment added abx This is usually stated with $Y$ an abelian variety. Then this implies the result for any subvariety of an abelian variety, for instance a curve of genus $\geq 1$.
May 31, 2023 at 12:09 comment added user197402 Really? I have never seen a result like this, can you explain it to me?
May 31, 2023 at 11:04 history edited user197402 CC BY-SA 4.0
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May 31, 2023 at 9:46 comment added abx If $Y$ is a curve of genus $\geq 1$, $\phi$ extends to a morphism $X\rightarrow Y$...
May 31, 2023 at 8:20 history asked user197402 CC BY-SA 4.0