Timeline for Integral inequality: an elementary proof?
Current License: CC BY-SA 4.0
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May 29, 2023 at 16:42 | history | edited | Terry Tao | CC BY-SA 4.0 |
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May 29, 2023 at 16:40 | vote | accept | Denis Serre | ||
May 29, 2023 at 16:30 | history | edited | Terry Tao | CC BY-SA 4.0 |
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May 29, 2023 at 16:24 | history | edited | Terry Tao | CC BY-SA 4.0 |
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May 29, 2023 at 16:06 | history | edited | Terry Tao | CC BY-SA 4.0 |
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May 29, 2023 at 15:36 | history | edited | Terry Tao | CC BY-SA 4.0 |
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May 29, 2023 at 15:31 | comment | added | Terry Tao | I simplified the argument to avoid this degradation of exponents by taking more advantage of the triangle inequality in the far field case. | |
May 29, 2023 at 15:30 | history | edited | Terry Tao | CC BY-SA 4.0 |
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May 29, 2023 at 10:32 | comment | added | Fedor Petrov | @DenisSerre Is it so much obvious that this constant is not $\infty$? | |
May 29, 2023 at 8:28 | comment | added | Denis Serre | @FedorPetrov As I mentioned in the question, the case $n=2$ is obvious, the integral being a constant. | |
May 29, 2023 at 8:10 | comment | added | Fedor Petrov | (for $n=2$ we may bound $R_1^{-1}R_2^4$ from below by $R_2^3$) | |
May 29, 2023 at 7:49 | history | edited | Denis Serre | CC BY-SA 4.0 |
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May 29, 2023 at 5:15 | comment | added | Fedor Petrov | The exponent of $R_1^{(n^2-3)/(n-1)}$ seems to be actually $(n-3)/(n-1)$, but still non-negative for $n>2$. | |
May 29, 2023 at 0:31 | history | answered | Terry Tao | CC BY-SA 4.0 |