Timeline for Do these properties characterize differentiation?
Current License: CC BY-SA 2.5
14 events
| when toggle format | what | by | license | comment | |
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| Feb 6, 2023 at 16:31 | comment | added | mathlander | See also: math.stackexchange.com/questions/4587371/… and math.stackexchange.com/questions/4588139/… | |
| Jan 19, 2022 at 15:45 | comment | added | Watson | (Yes, I also agree that there is an issue with the answer -- this was just to mention some other attempts that do not use $C^{\infty}$ directly) | |
| Jan 19, 2022 at 10:44 | comment | added | Steven Gubkin | @watson I agree with Ben Grossman in the comments there. The accepted answer is incorrect. | |
| Jan 19, 2022 at 10:26 | comment | added | Watson | See also math.stackexchange.com/questions/1682284 (to avoid using $C^{\infty}(\Bbb R)$... which requires differentiation to be defined). | |
| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Sep 30, 2014 at 22:27 | comment | added | Michael Hardy | I wonder what nice sets of conditions that include shift-equivariance are satisfied only by differentiation? | |
| Nov 4, 2010 at 6:20 | vote | accept | Steven Gubkin | ||
| Nov 4, 2010 at 5:47 | answer | added | Pedro Solorzano | timeline score: 1 | |
| Nov 4, 2010 at 5:23 | answer | added | Dick Palais | timeline score: 34 | |
| Nov 4, 2010 at 3:59 | comment | added | Mark Meckes | It's kind of dense, but you might be interested in this talk (I don't think a preprint is available yet): fields.utoronto.ca/audio/10-11/analysis/koenig | |
| Nov 4, 2010 at 3:59 | comment | added | KConrad | This question is closely related to the question mathoverflow.net/questions/25054/… and take a look at the string of comments I made on my own answer there for a discussion of how the product rule (in settings that include more rings than just the smooth functions on R) can be derived from more basic conditions. | |
| Nov 4, 2010 at 3:38 | comment | added | Ryan Budney | If $L$ is a derivation on $C^\infty(\mathbb R)$ it is a Lie derivative (wrt a vector field). See Conlon's "Differentiable Manifolds" book, pg 67. | |
| Nov 4, 2010 at 3:34 | answer | added | Todd Trimble | timeline score: 56 | |
| Nov 4, 2010 at 3:18 | history | asked | Steven Gubkin | CC BY-SA 2.5 |