Timeline for Is there a bounded sequence $(e_n)$ such that $e_n \in E_n$ and that $(e_n)$ does not have any convergent subsequence?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| May 28, 2023 at 17:34 | vote | accept | Analyst | ||
| May 28, 2023 at 17:25 | answer | added | Bill Johnson | timeline score: 6 | |
| May 27, 2023 at 15:42 | answer | added | Thomas Lehéricy | timeline score: 0 | |
| May 26, 2023 at 17:28 | comment | added | Analyst | @YemonChoi The existence of such sequence $(\lambda_n)$ is actually part of the assumption. | |
| May 26, 2023 at 17:27 | history | edited | Analyst | CC BY-SA 4.0 |
added 17 characters in body
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| May 26, 2023 at 17:16 | comment | added | Yemon Choi | If you mean (i) then you will need to impose some more conditions, to ensure that T has an infinite number of distinct eigenvalues... | |
| May 26, 2023 at 16:24 | comment | added | Analyst | @IosifPinelis I meant (i)... | |
| May 26, 2023 at 16:22 | comment | added | Iosif Pinelis | Your question is a bit unclear. Which of the following did you mean to ask: (i) "Is it true that for any such $E$ and $T$ there is a bounded sequence $(e_n)$ such that $e_n \in E_n$ for all $n$ and that $(e_n)$ does not have any convergent subsequence?" and (i) "Is it true that for some such $E$ and $T$ there is a bounded sequence $(e_n)$ such that $e_n \in E_n$ for all $n$ and that $(e_n)$ does not have any convergent subsequence?" | |
| May 26, 2023 at 15:58 | history | asked | Analyst | CC BY-SA 4.0 |