Timeline for Is every rational sequence topology homeomorphic?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| S May 26, 2023 at 16:28 | history | suggested | Steven Clontz | CC BY-SA 4.0 |
Fix typo (missing \not)
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| May 26, 2023 at 15:42 | review | Suggested edits | |||
| S May 26, 2023 at 16:28 | |||||
| May 26, 2023 at 15:17 | history | edited | Saúl RM | CC BY-SA 4.0 |
deleted 7 characters in body
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| May 26, 2023 at 15:16 | comment | added | Saúl RM | Yes, I will phrase the last part of the answer like your comment for more clarity | |
| May 26, 2023 at 15:10 | vote | accept | Steven Clontz | ||
| May 26, 2023 at 15:08 | comment | added | Steven Clontz | In particular, $cl_{T_f} A_0 = A_0 \cup f^{\leftarrow}[\{0\}]$ is distinct for each $f$, showing these topologies are all distinct. | |
| May 26, 2023 at 15:08 | history | edited | Saúl RM | CC BY-SA 4.0 |
deleted 42 characters in body
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| May 26, 2023 at 14:59 | history | answered | Saúl RM | CC BY-SA 4.0 |