Timeline for Surprisingly difficult limit of a sequence
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 29, 2023 at 11:14 | comment | added | J.Mayol | Yes, indeed. Sorry for this mess. The answer of @NoamD.Elkies is exactly answering this statement (and not the two previous iterations of my question, sorry). | |
| May 29, 2023 at 11:12 | history | edited | J.Mayol | CC BY-SA 4.0 |
added 2 characters in body
|
| May 26, 2023 at 20:04 | history | edited | Wlod AA | CC BY-SA 4.0 |
typo?
|
| May 26, 2023 at 18:13 | comment | added | Dave Benson | And did you mean $|\operatorname{Re}(a_n)|\to\infty$? | |
| May 26, 2023 at 18:02 | comment | added | J.Mayol | Yes, I meant that! | |
| May 26, 2023 at 17:34 | history | edited | Daniele Tampieri | CC BY-SA 4.0 |
Typo fixing+minor Math Jaxing
|
| May 26, 2023 at 13:06 | comment | added | Joe Silverman | Your definition of $a_n$ seems to be an absolute value, so it's already real. Did you mean to use parentheses? Also, use \left and \right to make them the right size, thus $$a_n = \left(\frac12+i\frac{\sqrt7}{2}\right)^n.$$ | |
| May 26, 2023 at 13:04 | comment | added | J.Mayol | Thank you, it is indeed hard! | |
| May 26, 2023 at 12:56 | comment | added | Noam D. Elkies | Asked and answered some years ago on Math Stack Exchange. The result is nontrivial but can be proved in several ways using known techniques. math.stackexchange.com/questions/705877/an-exotic-sequence | |
| May 26, 2023 at 12:43 | history | asked | J.Mayol | CC BY-SA 4.0 |