Timeline for Why can Hecke operators be regarded as finite flat cohomological correspondence?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| May 24, 2023 at 9:10 | vote | accept | Martin Tang | ||
| May 23, 2023 at 18:00 | history | edited | David Loeffler |
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| May 23, 2023 at 17:53 | answer | added | David Loeffler | timeline score: 3 | |
| May 23, 2023 at 16:07 | comment | added | Will Sawin | Of course, yes. | |
| May 23, 2023 at 12:57 | comment | added | Martin Tang | @WillSawin That's right. But I guess the composition is actually the diamond operator $\langle p \rangle$. | |
| May 23, 2023 at 11:00 | history | edited | Martin Tang | CC BY-SA 4.0 |
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| May 23, 2023 at 9:57 | comment | added | Will Sawin | I don't know if this is the best way to prove this, but there is an automorphism of $X_0(p)$ that exchanges $p_1$ and $p_2$ by sending $(E, H)$ to $(E/H, E[p]/H)$, so if one is finite flat then the other is. To check this is an automorphism you just need to check that its composition with itself is the identity. | |
| May 23, 2023 at 8:44 | history | asked | Martin Tang | CC BY-SA 4.0 |