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May 31, 2023 at 10:31 history edited user8469759 CC BY-SA 4.0
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May 31, 2023 at 10:24 comment added user8469759 I gave it more thought and I wrote an update. Would be nice if someone checked I did not write rubbish.
May 31, 2023 at 10:24 history edited user8469759 CC BY-SA 4.0
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May 26, 2023 at 6:33 comment added user8469759 I think this is also a good reference: google.co.kr/books/edition/Spline_Models_for_Observational_Data/…
May 22, 2023 at 15:23 history edited gmvh
Replaced "approximation-theory" by more pertinent "splines" tag
May 22, 2023 at 11:14 answer added rych timeline score: 3
May 22, 2023 at 10:36 comment added rych You're asking for the reference. I've tried to find a nice write-up on this too. Meanwhile, your solution looks okay to me. You've successfully linked the energy functional and biharmonic equation for the bending of a thin plate pinned at points. Indeed, the $\omega$ is the delta function in this case and so a solution will be a sum of (Green's) radial functions which you found in math.stackexchange.com/questions/4702167/… by introducing variables and so on (optionally using Fourier transform) and it is indeed the TPS plus a low-degree polynomial.
May 22, 2023 at 7:36 comment added user8469759 I'll wait for a more conclusive answer.
May 22, 2023 at 6:50 comment added user378654 I don't know, and maybe someone can answer more conclusively (it's clear you can minimize over some homogeneous space like $\dot{H}^2$, but you have to check whether you get unique solutions that way). I'd suggest thinking through the 1D Laplacian analogy: minimize $\int_{\mathbb{R}} (u')^2$ over $u$ with some finite number of points prescribed. You should get a piecewise linear function which has slope $0$ at the rightmost and leftmost (infinite) intervals as the only minimizer, so the energy form "forced" this nontrivial boundary condition at infinity.
May 22, 2023 at 4:37 comment added user8469759 What if I assume maybe $f \in W(\mathbb{R}^2)^{3,2} \cap C^3(\mathbb{R}^2)$? (so first 3 order derivatives in $L^2$ but also continuous?) Is it too restrictive?
May 22, 2023 at 4:26 comment added user378654 Actually minimizing would perhaps require more care, though, or at least some consideration of how your functions behave at infinity.
May 22, 2023 at 4:22 comment added user378654 Part of this is presumably related to the property of the biharmonic equation in the plane where isolated points have positive capacity, i.e. you can prescribe a boundary condition at points, unlike the Laplace equation (this property can be read off the fundamental solution: it's continuous at the origin). So you can minimize over the class of functions with prescribed values at the given set of points, and you'll get a minimizer in this class (and it will satisfy the EL equation on the complement of the set of points, analogously to what you derive with Lagrange multipliers formally).
May 22, 2023 at 1:48 history asked user8469759 CC BY-SA 4.0