Timeline for Is the spectrum of this ring Noetherian?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| May 22, 2023 at 5:10 | comment | added | KReiser | Crosspost from MSE. When cross-posting, please link all versions of your qeustion together. | |
| May 21, 2023 at 23:13 | history | became hot network question | |||
| May 21, 2023 at 16:57 | history | edited | YCor | CC BY-SA 4.0 |
formatting, removed tag
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| May 21, 2023 at 16:01 | answer | added | R. van Dobben de Bruyn | timeline score: 10 | |
| May 21, 2023 at 16:00 | history | edited | George | CC BY-SA 4.0 |
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| May 21, 2023 at 15:20 | history | edited | M.G. | CC BY-SA 4.0 |
some LaTeX and other minor fixes
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| May 21, 2023 at 15:20 | comment | added | R. van Dobben de Bruyn | Yes, the map $\mathbf F_2[x] \to \mathbf F_2[x^{1/2^\infty}]$ induces a universal homeomorphism on spectra, so $\operatorname{Spec} \mathbf F_2[x^{1/2^\infty}]$ is Noetherian as it is homeomorphic to $\operatorname{Spec} \mathbf F_2[x]$. See [Tags 04DF and 01S4(2)$\Leftrightarrow$(3)]. | |
| May 21, 2023 at 15:16 | history | edited | George | CC BY-SA 4.0 |
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| May 21, 2023 at 15:09 | history | asked | George | CC BY-SA 4.0 |