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The condition for mutually orthogonal latinLatin square

Suppose A$A$ and B$B$ are latin squareLatin squares of order n$n$. And suppose any column of A$A$ and any column of B$B$ have common entry only once. Then are A$A$ and B$B$ mutually orthogonal? 

I know the converse is true, but I don't know whether this is true, and how to prove this.

The condition for mutually orthogonal latin square

Suppose A and B are latin square of order n. And suppose any column of A and any column of B have common entry only once. Then are A and B mutually orthogonal? I know converse is true, but I don't know whether this is true, and how to prove this.

The condition for mutually orthogonal Latin square

Suppose $A$ and $B$ are Latin squares of order $n$. And suppose any column of $A$ and any column of $B$ have common entry only once. Then are $A$ and $B$ mutually orthogonal? 

I know the converse is true, but I don't know whether this is true, and how to prove this.

Source Link

The condition for mutually orthogonal latin square

Suppose A and B are latin square of order n. And suppose any column of A and any column of B have common entry only once. Then are A and B mutually orthogonal? I know converse is true, but I don't know whether this is true, and how to prove this.