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May 18, 2023 at 17:09 comment added Giorgio Metafune In this context the SMP follows from Harnack inequality. If $m$ is the infimum of $u$, then $v=u-m$ has infimum 0. If $v(x_0)=0$, then $\sup_B v \leq C \inf_B v=0$ for any ball $B$ containing $x_0$. The set of zeros of $v$ is then open and closed and $v=0$.
May 18, 2023 at 15:33 history edited YCor CC BY-SA 4.0
formatting, added tag
May 18, 2023 at 15:17 history asked user29999 CC BY-SA 4.0