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May 17, 2023 at 5:41 review Close votes
May 23, 2023 at 3:02
May 16, 2023 at 20:52 vote accept Dominic van der Zypen
May 16, 2023 at 20:29 answer added Joel David Hamkins timeline score: 7
May 16, 2023 at 20:04 comment added Joseph Van Name Every countable atomless Boolean algebra is isomorphic by a back-and-forth argument, so every countable atomless Boolean algebra is 'fractal', but the countable Boolean algebras cannot have a copy of $P(\omega)/\text{fin}$ since $P(\omega)/\text{fin}$ is uncountable.
May 16, 2023 at 19:57 history edited Dominic van der Zypen CC BY-SA 4.0
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May 16, 2023 at 19:48 history asked Dominic van der Zypen CC BY-SA 4.0