Skip to main content
16 events
when toggle format what by license comment
May 20, 2023 at 1:08 vote accept Philippe Gaucher
May 19, 2023 at 15:30 answer added Philippe Gaucher timeline score: 0
May 19, 2023 at 14:26 comment added darij grinberg One thing you can do is work with the sorting maps. The $i$-th sorting map $r_i$ changes the entries $x_i$ to $x_{i+1}$ to $\min\left\{x_i,x_{i+1}\right\}$ and $\max\left\{x_i,x_{i+1}\right\}$, respectively. The sorting maps generate a copy of the 0-Hecke monoid, if my memory doesn't cheat me. You can look at the category that they form when combined with the cofaces. This might be a smaller category than the one you're looking for, but well worth some study.
May 19, 2023 at 13:56 comment added darij grinberg Ah, those are the $[n]$s here! Interesting, but yes, the notation should be better...
May 19, 2023 at 8:37 history edited Philippe Gaucher CC BY-SA 4.0
added 66 characters in body
May 19, 2023 at 8:32 history edited Philippe Gaucher CC BY-SA 4.0
added 66 characters in body
May 19, 2023 at 8:26 comment added Philippe Gaucher @PeterLeFanuLumsdaine Probably $[1]^n$ is better than $[n]$ indeed. I use a different notations for presheaves.
May 19, 2023 at 7:50 comment added Peter LeFanu Lumsdaine This is a nice question, but may I suggest two notational changes might make it clearer? Denoting the cube posets $[1]^n$ or $I^n$ rather than $[n]$ (both certainly occur in the cubical sets literature, but elsewhere $[n]$ is much more widely used for $\{0,…,n\}$, which the cubical sense clashes badly with); and using something like $\square'$ instead of $\widehat{\square}$, since $\widehat{-}$ is standard notation for presheaf categories, and in particular $\widehat{\square}$ is commonly used for the category of cubical sets, so it’s very confusing to see it meaning a small cube category?
May 19, 2023 at 6:21 history edited Philippe Gaucher CC BY-SA 4.0
edited body
May 19, 2023 at 6:20 comment added Philippe Gaucher @darijgrinberg $[n]=\{0<1\}^n$, not $\{1<\dots<n\}$. For example, the map $(x_1,x_2)\mapsto (x_2,x_1)$ is strictly increasing. Poset means partially ordered set.
May 19, 2023 at 1:59 comment added darij grinberg By "posets" you mean finite sets? And how do you get symmetries in that category? And isn't the only strictly increasing map $f : [n] \to [n]$ the identity?
May 19, 2023 at 1:58 history edited darij grinberg CC BY-SA 4.0
added 7 characters in body
May 18, 2023 at 3:03 history edited Philippe Gaucher CC BY-SA 4.0
deleted 16 characters in body
May 18, 2023 at 2:55 history edited Philippe Gaucher CC BY-SA 4.0
added 2013 characters in body
May 16, 2023 at 15:06 history edited Philippe Gaucher CC BY-SA 4.0
added 5 characters in body
May 16, 2023 at 14:59 history asked Philippe Gaucher CC BY-SA 4.0