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Timeline for Approximation to ratio distribution

Current License: CC BY-SA 4.0

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May 19, 2023 at 22:11 vote accept Hazards
May 16, 2023 at 22:41 comment added Gerry Myerson Why are all these mathcal letters showing up as open squares on my screen?
May 16, 2023 at 18:54 comment added Hazards meaning that $\mathcal{X}$ and $\mathcal{Y}$ are non degenerate
May 15, 2023 at 22:17 comment added Mark Schultz-Wu @Hazards what precisely is your "niceness" assumption? It is pretty well-known that the ratio of two Gaussians is Cauchy, i.e. even when $X, Y$ are individually nice, $X/Y$ need not be nice.
May 15, 2023 at 20:20 history edited Hazards
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May 15, 2023 at 19:24 answer added Iosif Pinelis timeline score: 2
May 15, 2023 at 18:12 comment added Hazards @JamesMartin exactly that! I apologize if I did not express myself too clearly from the start
May 15, 2023 at 18:11 comment added James Martin OK - makes sense. Just to make it completely clear - I think you're saying that if $X$ and $Y$ are independent with distributions $\mathcal{X}$ and $\mathcal{Y}$ respectively, then their product $XY$ has distribution $\mathcal{Z}$. And presumably your samples $X_1, X_2, \dots, X_m$ and $Z_1, Z_2, \dots, Z_n$ from $\mathcal{X}$ and $\mathcal{Z}$ are independent of each other.
May 14, 2023 at 15:31 comment added Hazards What I am trying to find is a method that could provide me the distribution of $\mathcal Y$ given that I know the distribution of $\mathcal X$ and $\mathcal Z$ knowing that they are related by the fact that the product of $\mathcal{X}$ and $\mathcal Y$ is $\mathcal Z$ in distribution (assuming everything is "nice")
May 14, 2023 at 0:05 comment added James Martin What does "$\text{law}(\mathcal X)\cdot\text{law}(\mathcal Y) = \text{law}(\mathcal Z)$" mean?
S May 13, 2023 at 17:23 review First questions
May 13, 2023 at 17:43
S May 13, 2023 at 17:23 history asked Hazards CC BY-SA 4.0