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May 27, 2023 at 7:51 comment added Evgeny Shinder I believe it is not known whether exceptional divisors for resolutions of rational singularities are always acyclic, as this can depend on singularities of the exceptional divisors themselves. What is known is that for a snc resolution, the fibers are acyclic, see Lemma 2.5 in arxiv.org/pdf/2212.06786.pdf.
May 13, 2023 at 3:23 comment added Ben C @JasonStarr this is a very interesting strategy,. however I must say I don't understand why the corresponding cohomological vanishing statement for X^1 holds or how you draw your confusion from this equality of hodge structures
May 13, 2023 at 2:27 comment added naf The pullback map $\mathrm{Pic}^0(X) \to \mathrm{Pic}^0(\tilde{X})$ is an isomorphism since it is always injective for a resolution of a normal variety and then it suffices to know that it is surjective on tangent spaces which follows from the Leray spectral sequence. This is all that is needed to see that the map extends, since for any nonconstant map $f: Z \to A$ where $A$ is an abelian variety---we apply this to a fibre of the resolution---the pullback map on $\mathrm{Pic}^0$ is never zero (reduce to the case $Z$ is a smooth projective curve).
May 12, 2023 at 21:54 comment added Jason Starr Let $\widetilde{X}^1$ be a desingularization of the closure of the smooth locus in $\widetilde{X}\times_X \widetilde{X}$ with its projections $\text{pr}_i:\widetilde{X}^1 \to \widetilde{X}$, for $i=0,1$. By hypothesis, the natural maps $\mathcal{O}_{\widetilde{X}} \to R\text{pr}_{i,*} \mathcal{O}_{\widetilde{X}^1}$ are quasi-isomorphisms. Thus, via the Leray spectral sequence, the pullback maps $H^q(\widetilde{X},\mathcal{O}_{\widetilde{X}})\to H^q(\widetilde{X}^1,\mathcal{O}_{\widetilde{X}^1})$ maps are also isomorphisms. For $q=1$, this gives equality of the weight-$1$ Hodge structures.
May 12, 2023 at 21:47 history edited Ben C CC BY-SA 4.0
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May 12, 2023 at 19:18 history asked Ben C CC BY-SA 4.0