Timeline for Does maximally incompleteness cause nonvanishing of the extension of maximal ideal of a valuation ring by rank 1 free module?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| S May 22, 2023 at 13:07 | history | bounty ended | CommunityBot | ||
| S May 22, 2023 at 13:07 | history | notice removed | CommunityBot | ||
| S May 14, 2023 at 11:29 | history | bounty started | XYC | ||
| S May 14, 2023 at 11:29 | history | notice added | XYC | Draw attention | |
| May 14, 2023 at 11:28 | history | edited | XYC | CC BY-SA 4.0 |
added 921 characters in body
|
| May 12, 2023 at 6:43 | history | edited | XYC | CC BY-SA 4.0 |
added 251 characters in body
|
| May 12, 2023 at 6:36 | comment | added | XYC | @LaurentMoret-Bailly Thank you for pointing out. I made a mistake here and just edited it. But it makes the deduction $\operatorname{Ext}^1(\mathfrak{m},R)=0\implies\operatorname{Ext}^1(A,S)=0$ even harder. | |
| May 12, 2023 at 4:56 | comment | added | Laurent Moret-Bailly | About part (2) of Matlis' result: it is not true that torsion-free of rank 1 implies free, unless $S$ is finitely generated. | |
| May 11, 2023 at 19:32 | history | edited | XYC | CC BY-SA 4.0 |
added 15 characters in body
|
| May 11, 2023 at 19:24 | history | asked | XYC | CC BY-SA 4.0 |