Timeline for Existence of integer sequence under simultaneous constraints
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| May 10, 2023 at 23:49 | comment | added | Peter Taylor | If there is a fixpoint $f(m)=m$ then $f(a_m) = a_{m+1} = a_{f(m)+1} = a_m$ and the sequence has a non-constant prefix followed by a constant tail. | |
| May 10, 2023 at 23:00 | comment | added | Wojowu | $f$ defined by $f(0)=1,f(2k-1)=2k,f(2k)=2k-1$ for all $k>0$ seems to work. I have no idea about classification. | |
| May 10, 2023 at 22:40 | history | edited | TheSimpliFire | CC BY-SA 4.0 |
edited body
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| May 10, 2023 at 22:27 | comment | added | Wojowu | I'm assuming you also want such a sequence $a_n$ to exist - otherwise the implication is vacuously true. | |
| May 10, 2023 at 22:08 | history | asked | TheSimpliFire | CC BY-SA 4.0 |