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May 11, 2023 at 7:33 comment added Tom De Medts @LorenzoDelVecchiopontopolos That depends on the field. For instance, the specific example I gave is indeed isomorphic to the group algebra $k\mathbb{Z}_2$ if $\operatorname{char}(k) \neq 2$, but not if $\operatorname{char}(k) = 2$. In general, the group algebra $k\mathbb{Z}_n$ is isomorphic to the Hopf algebra of functions from $\mathbb{Z}_n$ to $k$ if and only if the polynomial $f(x) = x^n - 1$ has $n$ different roots in $k$ (in other words, if it splits over $k$ and has no multiple roots).
May 10, 2023 at 20:17 comment added Lorenzo Del Vecchiopontopolos Thanks for the reference. But I thought that for prime order, all finite-dimensional Hopf algebras were isomorphic . . .
May 10, 2023 at 18:24 comment added Tom De Medts @LorenzoDelVecchiopontopolos It's not isomorphic to the group Hopf algebra of $\mathbb{Z}_2$. It's the Hopf algebra of functions from $\mathbb{Z}_2$ to $k$. (This is the second example on en.wikipedia.org/wiki/Hopf_algebra#Examples.)
May 10, 2023 at 17:03 comment added Lorenzo Del Vecchiopontopolos Sorry but I don't see how this is isomorphic to the group Hopf algebra of $\mathbb{Z}_2$.
May 10, 2023 at 14:35 history answered Tom De Medts CC BY-SA 4.0