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May 23, 2023 at 11:18 vote accept Brian Lins
May 13, 2023 at 17:36 comment added Moishe Kohan I find it very surprising that somebody can ask a question about contractible spaces and not be familiar with basics of homology. I also have no idea how one can justify the sentence "This is certainly true if $V$ is a compact real analytic manifold (without boundary)" (from your post) without using homology.
May 12, 2023 at 15:36 comment added Moishe Kohan Did you understand the answer?
May 10, 2023 at 2:35 answer added Moishe Kohan timeline score: 4
May 9, 2023 at 16:16 comment added Brian Lins Yes, I guess my question could be generalized by only requiring the analytic function $f$ be defined on an open subset of $\mathbb{R}^n$ and then assuming that the variety $V$ defined by $f$ is contractible and compact.
May 9, 2023 at 15:05 comment added Z. M In your edit, you seem to impose that the function is globally defined, but the usual definition of complex analytic sets is defined locally being a zero set of local analytic functions.
May 9, 2023 at 14:58 comment added Brian Lins Thanks, I've edited the question.
May 9, 2023 at 14:57 history edited Brian Lins CC BY-SA 4.0
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May 9, 2023 at 14:55 comment added Moishe Kohan You should update your question accordingly (since there are inequivalent definitions in the literature).
May 9, 2023 at 14:46 comment added Brian Lins A real analytic variety is the set of zeros of one or more real analytic functions (in this case, real-valued functions that are real analytic on $\mathbb{R}^n$). Of course, a real analytic variety that is defined by more than one real analytic function $f_1, f_2, \ldots, f_k$ can be expressed as the zero set of $f_1^2 + f_2^2 + \ldots f_k^2$.
May 9, 2023 at 13:47 comment added Moishe Kohan What is your definition of a "real analytic variety in $R^n$?"
May 9, 2023 at 13:25 answer added Francesco Polizzi timeline score: 2
May 9, 2023 at 12:11 history asked Brian Lins CC BY-SA 4.0