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May 8, 2023 at 20:51 vote accept banana
May 8, 2023 at 20:51 vote accept banana
May 8, 2023 at 20:51
May 7, 2023 at 6:17 comment added Fedor Petrov if $j_1<j_2<\ldots<j_i$ are first elements of $i$ special pairs, then $j_1<j_2-1<j_3-2<\ldots <j_i-i+1\leqslant n-i+1$ are distinct numbers between 1 and $n-i+1$
May 7, 2023 at 4:49 comment added Alapan Das @banana Consider the $i$ pairs $j,j+1$ as $i$ boxes (which may includes $n+1$ as well). Now put the remaining $n-2i+1$ numbers can be arranged in $i+1$ ( the places in between the boxes and on the sides) in $\binom{n-i+1}{i}$ ways.
May 6, 2023 at 23:59 comment added banana Could you explain why there are nCr (𝑛−𝑖+1, i) number of ways to choose 𝑖 special pairs?
May 6, 2023 at 20:49 history answered Fedor Petrov CC BY-SA 4.0