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May 7, 2023 at 15:21 vote accept UVIR
May 7, 2023 at 15:12 history edited UVIR CC BY-SA 4.0
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May 7, 2023 at 3:32 answer added Wojowu timeline score: 9
May 7, 2023 at 0:18 comment added Gerry Myerson "monomial polynomials"? Do you mean, monic polynomials, UVIR?
May 6, 2023 at 22:00 answer added R. van Dobben de Bruyn timeline score: 6
May 6, 2023 at 21:23 history edited LSpice CC BY-SA 4.0
Consistent notation
May 6, 2023 at 21:21 comment added LSpice @UVIR, re, use Zorn to let $A$ be a maximal integral extension of $\mathbb Z$ such that there is a ring map $A \to \overline{\mathbb F_p}$, then show that, if $A$ is not all of $\overline{\mathbb Z}$, we can extend any given ring map $A \to \overline{\mathbb F_p}$ to a larger ring. \\ TeX note: \mathbb takes a following argument (unlike, e.g., \bf), so, e.g., {\mathbb F} is the same as {\mathbb{F}}, and you might as well drop the outer braces for \mathbb{F} (or \mathbb F).
May 6, 2023 at 20:32 history edited UVIR CC BY-SA 4.0
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May 6, 2023 at 19:37 review Close votes
May 12, 2023 at 3:11
May 6, 2023 at 19:24 comment added UVIR @R. van Dobben de Bruyn Can you clarify a little bit more, maybe write an answer, or give me a reference? Thanks!
May 6, 2023 at 19:14 comment added R. van Dobben de Bruyn Yes, $\operatorname{Hom}_{\text{Ring}}(\overline{\mathbf Z},\overline{\mathbf F}_p) \neq \varnothing$. In fact this set has a natural continuous action of $\operatorname{Gal}(\overline{\mathbf Q}/\mathbf Q)$ by precomposition and by $\operatorname{Gal}(\overline{\mathbf F}_p/\mathbf F_p)$ by postcomposition. I think that the $\operatorname{Gal}(\overline{\mathbf Q}/\mathbf Q)$-action is transitive, and the stabiliser of a homomorphism is the inertia group of its kernel.
May 6, 2023 at 18:59 comment added UVIR @R. van Dobben de Bruyn Then is there such a map, whether canonical or not?
May 6, 2023 at 18:56 comment added R. van Dobben de Bruyn Every prime ideal $\mathfrak p \subseteq \overline{\mathbf Z}$ dividing $p\overline{\mathbf Z}$ has $\overline{\mathbf Z}/\mathfrak p \cong \overline{\mathbf F}_p$, but there is no preferred choice (neither of $\mathfrak p$ nor of this isomorphism). In fact, even saying the algebraic closure of $\mathbf F_p$ (or the set of algebraic integers) doesn't make sense; it is only defined up to non-canonical isomorphism.
May 6, 2023 at 18:53 history asked UVIR CC BY-SA 4.0