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May 7, 2023 at 8:09 vote accept Jakobian
May 5, 2023 at 20:40 history edited LSpice CC BY-SA 4.0
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May 5, 2023 at 15:40 answer added Jakobian timeline score: 7
May 5, 2023 at 15:08 comment added Jakobian @Anonymous Ah I see! If $x$ is in the remainder of the Stone-Cech compactification of $\beta\mathbb{Q}\setminus\mathbb{Q}$, then the character at that point is uncountable by above argument. But if $x\in \beta\mathbb{Q}\setminus \mathbb{Q}$, then since character of a point is the same for any dense embedding, it must be equal to $\chi(x, \beta\mathbb{Q})$ which again by above argument is uncountable.
May 5, 2023 at 13:42 comment added Anonymous I don't know where this is explicitly stated--it might be in the Walker book on the Stone-Cech compactification--but it is not hard. If $p$ is a point of first countability of $\beta X \setminus X$, then $\beta X \setminus \{p\}$ is $\sigma$-compact and therefore normal. But if $a = (a_n)$ a sequence in $X$ that converges to $p$, then $\{a_n: n = 1, 2, ...\}$ is closed in $X$ but a function which alternates between $0$ and $1$ on that set does not extend to $p$.
May 5, 2023 at 13:03 comment added Jakobian @Anonymous do you have a reference?
May 5, 2023 at 11:51 comment added Anonymous $\beta \mathbb{Q}$ has a dense metrizable subset (and points of first countability) whereas $\beta (\beta {\mathbb{Q}} \setminus {\mathbb{Q}})$ has neither.
May 5, 2023 at 0:18 comment added Joseph Van Name For each partition of $\beta\mathbb{Q}$ into two components $A,B$, one of those components has a non-trivial convergent sequence. I don't see the same thing happening with $\beta(\beta\mathbb{Q}\setminus\mathbb{Q})$ but I am currently too busy to write and check the proof.
May 4, 2023 at 21:56 history edited Jakobian CC BY-SA 4.0
rewrote what I wrote previously for better clarity
May 4, 2023 at 21:42 history edited Jakobian CC BY-SA 4.0
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May 4, 2023 at 21:35 comment added Jakobian @Gro-Tsen Yes, see edit2
May 4, 2023 at 21:34 history edited Jakobian CC BY-SA 4.0
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May 4, 2023 at 21:18 comment added Gro-Tsen Can you justify or provide a reference for the statement of the first sentence? Is it supposed to be a well-known or trivial fact?
May 4, 2023 at 19:58 history edited Jakobian CC BY-SA 4.0
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May 4, 2023 at 19:20 comment added R. van Dobben de Bruyn At a first glance, it seems to me they might have wildly different cardinalities. Or did you try this already?
May 4, 2023 at 15:41 history asked Jakobian CC BY-SA 4.0