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May 3, 2023 at 7:36 history edited JKDASF CC BY-SA 4.0
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May 3, 2023 at 7:15 answer added Dave Benson timeline score: 1
May 3, 2023 at 6:36 comment added Achim Krause It depends on how $G$ and $k^{\times}$ are given. But if $G$ is given by a list of its elements, and $k^{\times} $ as an explicit finitely generated abelian group, you have a presentation of $C^1(G, k^{\times}) $ and can compute whether your cocycle is in the image of the coboundary map using Smith normal form.
May 3, 2023 at 6:15 history asked JKDASF CC BY-SA 4.0