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May 3, 2023 at 6:51 comment added user493645 @JosephVanName I understand this, but I would like to get the same $\Sigma$ ($U$ in your notation) for all $i$. This is stronger, but I think it is likely to be true: for $d=1$ (i.e., when $A_i, B_i \in \mathbb{C}$) it can be seen easily.
May 2, 2023 at 16:46 comment added Joseph Van Name When we set $x_i=1$ and $x_j=0$ for $j\neq i$, we should get $A_iA_i^*=B_iB_i^*$. This implies that $A_i=B_iU_i$ for some unitary $U_i$.
May 2, 2023 at 16:02 history edited Christian Remling CC BY-SA 4.0
added 16 characters in body
May 2, 2023 at 10:15 history edited Rodrigo de Azevedo CC BY-SA 4.0
Scalars are usually written to the left of matrices, lest they be confused for vectors
May 2, 2023 at 10:13 comment added Fedor Petrov Maybe $B=\Sigma A$?
May 2, 2023 at 8:45 history asked user493645 CC BY-SA 4.0