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May 1, 2023 at 7:20 vote accept Dominic van der Zypen
Apr 30, 2023 at 20:26 answer added Saúl RM timeline score: 7
Apr 30, 2023 at 20:20 comment added Sam Hopkins The famous Johnson graph $J(n,k)$ (en.wikipedia.org/wiki/Johnson_graph) is the graph whose vertices are $k$-subsets of $[n] = \{1,\ldots,n\}$, with an edge between vertices if their intersection has size $k-1$. You are asking about the analogous graph "$J(\infty,k)$," where the subsets are now of $\mathbb{N}$ instead of $[n]$. Specifically, you are asking whether this $J(\infty,k)$ has a Hamiltonian path. For comparison, it is known that all the $J(n,k)$ have Hamiltonian paths (in fact, Hamiltonian cycles). Anyways, this doesn't answer your question, but may be a starting point.
Apr 30, 2023 at 19:59 history asked Dominic van der Zypen CC BY-SA 4.0