Timeline for Dimension of a kernel of a linear map
Current License: CC BY-SA 4.0
12 events
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Sep 24 at 2:47 | history | edited | Hung-Hsun Yu | CC BY-SA 4.0 |
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May 2, 2023 at 8:34 | comment | added | Marcos | @მამუკაჯიბლაძე I've tried to generalize this question in a more general setting using your idea of $2$-cocycle in mathoverflow.net/questions/445969/…. | |
Apr 29, 2023 at 7:16 | comment | added | მამუკა ჯიბლაძე | Nice! An (obvious) observation: your $F$ is a 2-cocycle. I suspect this is not a coincidence - @Marcos mentions in a comment that all this has to do with computing second (co?)homology of something... | |
Apr 29, 2023 at 5:49 | comment | added | Hung-Hsun Yu | Thanks for catching the typo! The notation $[x^ay^bz^c]f(x,y,z)$ is the abbreviation for the coefficients of $x^ay^bz^c$ in $f(x,y,z)$. | |
Apr 29, 2023 at 5:48 | history | edited | Hung-Hsun Yu | CC BY-SA 4.0 |
added 8 characters in body
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Apr 28, 2023 at 23:42 | history | bounty ended | Marcos | ||
Apr 28, 2023 at 23:42 | vote | accept | Marcos | ||
Apr 28, 2023 at 9:45 | comment | added | Marcos | Moreover, I don't folow what $[x^ay^bz^c]F(x+z,y)+F(z,y)=1$ means. The $[x^ay^bz^c]$ is multiplication by $x^ay^bz^c$? Because in such case the equation feels weird. | |
Apr 28, 2023 at 9:28 | comment | added | Marcos | Also, the second sumand should be $\sum_{i<j<n+1}\binom{n+1-i}{j-i}x^iy^{n+1-j}z^{j-i}$ | |
Apr 28, 2023 at 8:59 | comment | added | Marcos | Thanks!! Just a couple of things. If I understood your proof correctly the set you defined as $S$ should be $I$. Also, what does the notation $a\oplus b$ mean? The reason why I care about this map is because it appears as the differential map used to compute the homolgy of a certain group, so I wasn't aware of the polynomial interpretation of the formula you gave. | |
Apr 27, 2023 at 21:57 | review | Late answers | |||
Apr 27, 2023 at 22:59 | |||||
Apr 27, 2023 at 21:34 | history | answered | Hung-Hsun Yu | CC BY-SA 4.0 |