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Apr 27, 2023 at 20:27 history edited Glorfindel CC BY-SA 4.0
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Apr 27, 2023 at 20:10 comment added Carlo Beenakker denote the error in $\pi$ by $\delta\pi$, then $\delta\pi=(\pi/2m)(1/\phi_m)\delta\phi_m$; the error $\delta\phi_m$ should be much less than unity, so $\delta\pi\ll (\pi/2m)(1/\phi_m)$.
Apr 27, 2023 at 18:12 history edited japjap CC BY-SA 4.0
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S Apr 27, 2023 at 18:07 review First questions
Apr 27, 2023 at 20:27
S Apr 27, 2023 at 18:07 history asked japjap CC BY-SA 4.0