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Nov 7, 2023 at 19:34 vote accept Peter Gerdes
Apr 29, 2023 at 18:23 comment added Joe Miller Peter: Yes, exactly. The coding is a little trickier because you need all of the sets to simultaneously tell you whether you're forcing truth or falsity. The second and third proofs mentioned in 喻 良's answer use different tricks to ensure that this is possible.
Apr 29, 2023 at 1:18 answer added 喻 良 timeline score: 5
Apr 28, 2023 at 19:15 comment added Peter Gerdes As opposed to the Posner-Robinson approach where we use n plus some fast growing function in C to bound the length of sigma (which won't extend to allowing us to join a hyperimmune free degrees A to arbitrary degree above 0' join A).
Apr 28, 2023 at 19:14 answer added Peter Gerdes timeline score: 2
Apr 28, 2023 at 17:27 comment added Peter Gerdes By Jockusch-Shore style do you mean where we add 0^n^1^\sigma and use membership of n in the set to code whether we force the truth or falsity?
Apr 28, 2023 at 4:29 comment added Joe Miller I don't know why 喻 良 is being so cheeky. The multiple degree version of Posner–Robinson is Theorem 3 in the Posner–Robinson paper. And he knows of two Jockusch–Shore style proofs (unpublished, as of yet)
Apr 27, 2023 at 11:44 comment added 喻 良 You may find the answer in the Posner-Robinson's paper.
Apr 27, 2023 at 3:21 comment added Peter Gerdes I'm guessing that this can be done using the technique of e-splitting extensions in the proof of the complementation theorem to manage to avoid computing $D_1$ but it's complicated enough that I'm not sure.
Apr 27, 2023 at 3:17 history asked Peter Gerdes CC BY-SA 4.0