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May 1, 2023 at 16:22 comment added Alexandre Eremenko The conjecture is that if both { z:u(z)>0} and { z: u(z)<0} are connected then your assertion about areas must be true. But if only one of them is connected, probably not. Both statements look plausible but difficult to prove.
May 1, 2023 at 14:52 comment added Re_0 Yes! I have been wondering if there is any proof or counterexample of this case ( the positive part and negative part are both connected)
Apr 28, 2023 at 12:05 comment added Alexandre Eremenko @Sam and Jim: do you also want $\{ z:u(z)<0\}$ to be connected?
Apr 28, 2023 at 0:38 vote accept Re_0
Apr 28, 2023 at 0:27 comment added Re_0 Oh, you are right and I am afraid I forgot to assume $\{z: u(z)>0\}$ is also a region.
Apr 27, 2023 at 18:12 comment added Alexandre Eremenko I repeat that the set $\{ z:u(z)>0\}$ is ALWAYS simply connected.
Apr 27, 2023 at 16:03 comment added Re_0 Then the positive part is not simply connected in this example, which does not satisfy the condition.
Apr 27, 2023 at 10:56 comment added Alexandre Eremenko Each component of the set $\{ z:u(z)>0\}$ for any harmonic function is simply connected; this followd from the Maximum/Minimum Principle. But the number of components can be large.
Apr 27, 2023 at 4:16 comment added Re_0 But I'm wondering if the positive part $\{x\in B_1(0): u(x)>0\}$ of such a harmonic function $u(z)$ is always simply connected?
Apr 26, 2023 at 13:00 history edited Alexandre Eremenko CC BY-SA 4.0
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Apr 26, 2023 at 12:51 history answered Alexandre Eremenko CC BY-SA 4.0