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Jul 5, 2023 at 11:19 comment added THC @ArnoFehm: does Geyer use Choice to obtain that result ?
Apr 20, 2023 at 13:45 comment added THC @ArnoFehm: so they are finite of size 2 ?
Apr 20, 2023 at 13:38 comment added Arno Fehm Will Sawin answers the first question, and the structure of that subgroup is known (a result by Fried-Haran-Völklein). The abelian subgroups are also known, in particular every elementary 2-abelian subgroup is in fact cyclic (this I think is an older result by Geyer), see this answer: mathoverflow.net/a/352952/50351
Apr 20, 2023 at 12:58 comment added Will Sawin The subgroup generated by all involutions is the Galois group of $\overline{\mathbb Q}$ over the maximal totally real extension of $\mathbb Q$ as this is the fixed field of all the complex conjugations.
Apr 20, 2023 at 10:49 history asked THC CC BY-SA 4.0