Timeline for Riemann-Liouville integral of $f$ is zero implies $f =0$ a.e
Current License: CC BY-SA 4.0
3 events
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| Apr 19, 2023 at 13:39 | comment | added | Grandes Jorasses | I also don't understand why computing the Fourier transform of $g$ is useful (by the way, are you sure about the multiplication by $|\xi|^{-1/2}$?) and why it proves that $\hat{F}$ is supported at the origin. | |
| Apr 19, 2023 at 12:30 | comment | added | Grandes Jorasses | Thank you! I do not understand why $\hat{F} \hat{g} = 0$. Isn't the Fourier transform of $0$ just $0$ concentrated at the origin? | |
| Apr 19, 2023 at 12:09 | history | answered | Bazin | CC BY-SA 4.0 |