Timeline for Hopf algebra of representative k-valued functions of an abstract group
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 20, 2023 at 0:25 | comment | added | user502786 | Exactly @Benjamin | |
| Apr 18, 2023 at 21:44 | comment | added | Benjamin Steinberg | I see. You want characters of R(G) not G | |
| Apr 18, 2023 at 21:06 | comment | added | user502786 | Let T and S two characters, i.e algebra maps from R(G) to k. Then (T*S)(f)=m(T \tensor S) \delta (f), for all f \in R(G) | |
| Apr 18, 2023 at 11:45 | comment | added | Benjamin Steinberg | I think only pointwise product of characters gives you a character. | |
| Apr 18, 2023 at 10:55 | comment | added | Benjamin Steinberg | How do you define the convolution of characters so that you get another character? | |
| Apr 18, 2023 at 4:06 | comment | added | user502786 | And G i can suppose that it is embedded in it under some assumption on G. | |
| Apr 18, 2023 at 4:03 | comment | added | user502786 | no it is not commutative unless G is, as in fact it is a group under the convolution product | |
| Apr 18, 2023 at 2:01 | comment | added | Benjamin Steinberg | But XR(G) is commutative is it not? So why would G be embedded in XR(G)? | |
| Apr 18, 2023 at 1:27 | comment | added | user502786 | Yes i mean hopf algebra of representative functions, if we take in particular the context of tannaka-krein duality, and G a group embedded in the characters group X(R(G)) of R(G), such that R(G) is isomorphic to R(X(R(G)) as hopf algebras, does this implies that G isomorphic to X(R(G)) ? | |
| Apr 17, 2023 at 19:47 | history | answered | Benjamin Steinberg | CC BY-SA 4.0 |