Skip to main content
deleted 841 characters in body
Source Link

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of $z$ edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p_i$ be the parameter of $X_i$, and $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left(\sum_{i=1}^{z} X_i<pz-\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left(\sum_{i=1}^{z} X_i>pz+\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of $z$ edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p_i$ be the parameter of $X_i$, and $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left(\sum_{i=1}^{z} X_i<pz-\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left(\sum_{i=1}^{z} X_i>pz+\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?

Notice removed Canonical answer required by CommunityBot
Bounty Ended with no winning answer by CommunityBot
Notice added Canonical answer required by Penelope Benenati
Bounty Started worth 50 reputation by Penelope Benenati
edited body
Source Link

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of $z$ edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p_i$ be the parameter of $X_i$, and $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i<pz-\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$$$\mathbb{P}\left(\sum_{i=1}^{z} X_i<pz-\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i>pz+\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$$$\mathbb{P}\left(\sum_{i=1}^{z} X_i>pz+\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p_i$ be the parameter of $X_i$, and $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i<pz-\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i>pz+\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of $z$ edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p_i$ be the parameter of $X_i$, and $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left(\sum_{i=1}^{z} X_i<pz-\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left(\sum_{i=1}^{z} X_i>pz+\lambda\right)\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

added 33 characters in body
Source Link

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p_i$ be the parameter of $X_i$, and $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i<pz-\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i>pz+\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i<pz-\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i>pz+\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

Let $G(V,E)$ be a connected simple graph, where $V$ and $E$ denote respectively its vertex and the edge set respectively. Let $f: V\to \{-1,1\}$ a function mapping each vertex to a value in $\{-1,1\}$.

Let $T(E_T,V)$ be a uniformly generated random spanning tree of $G$, where $E_T\subseteq E$ denotes its edge set. Given any vertex $v\in V$, we denote by $D_T(v)$ its degree in $T$ and by $S_T(v)$ the sum of $f(v')$ over all vertices $v'$ adjacent to $v$ in $T$.


Question: How can we prove (or disprove) that, for all connected simple graphs $G(V, E)$, all vertices $v\in V$, and all functions $f:V\to\{1,-1\}$, we have $$\mathbb{E}[S_T(v)]\cdot\mathbb{E}\left[\frac{S_T(v)}{D_T(v)}\right]\ge 0\,,$$ where the expectation is taken over the generation of the random spanning tree $T$ of $G$?



Observations: I think this concentration result might be helpful. Let $X_1, X_2, \ldots, X_{z}$ be the Bernoulli random variables corresponding to any subset of edges of $E$ with $2\le z\le |E|$ where, for each $i\in\{1,2,\ldots, z\}$, we have $X_i=1$ iff the $i$-th edge of such subset of $E$ is included in $E_T$. Note that $\{X_i\}_{i=1}^{z}$ are negatively correlated as well as the random variables $\{1-X_i\}_{i=1}^{z}$. Let $p_i$ be the parameter of $X_i$, and $p:=\frac{1}{z}\sum_{i=1}^{z}p_i$. Using a Chernoff's bound for negatively correlated random variables we have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i<pz-\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,,$$ and therefore we also have $$\mathbb{P}\left[\sum_{i=1}^{z} X_i>pz+\lambda\right]\le\exp\left(-\frac{\lambda^2}{2pz}\right)\,.$$

Added concentration inequalities hoping they can help
Source Link
Loading
Added concentration inequalities hoping they can help
Source Link
Loading
Raphrasing
Source Link
Loading
deleted 4 characters in body
Source Link
Loading
Added $f$ in the question with a universal quantifier
Source Link
Loading
added 4 characters in body
Source Link
Loading
Source Link
Loading