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Apr 14, 2023 at 14:41 review Close votes
Apr 30, 2023 at 3:06
Apr 14, 2023 at 14:22 history edited LSpice CC BY-SA 4.0
Typos
Apr 14, 2023 at 13:39 comment added LSpice Would $e^{x\cdot\ln(p)}$ do?
Apr 14, 2023 at 13:23 comment added Achim Krause It doesn't seem likely that this is possible. For fixed $p$, if you want to find a $Q$ such that $x^T Q x = p_ip_jp_k$ whenever $x$ is the vector with $1$'s at $i,j,k$, you're looking at $\binom{n}{3}$ linear equations constraining the $n^2$ many entries of $Q$. And they look completely independent. I bet once $n\geq 9$ (where $\binom{n}{3}>n^2$) there is no such $Q$ for generic $p$ anymore.
S Apr 14, 2023 at 13:00 review First questions
Apr 14, 2023 at 13:00
S Apr 14, 2023 at 13:00 history asked christian_lee CC BY-SA 4.0