Timeline for Categorifying the definition of a principal $G$ bundle
Current License: CC BY-SA 4.0
11 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Apr 15, 2023 at 9:28 | vote | accept | Spai | ||
Apr 13, 2023 at 9:04 | answer | added | Konrad Waldorf | timeline score: 8 | |
Apr 12, 2023 at 20:24 | answer | added | Dmitri Pavlov | timeline score: 4 | |
Apr 12, 2023 at 12:20 | history | edited | LSpice | CC BY-SA 4.0 |
Consistent TeX
|
Apr 12, 2023 at 11:52 | answer | added | Tim Porter | timeline score: 6 | |
Apr 12, 2023 at 7:56 | comment | added | მამუკა ჯიბლაძე | Furthermore these are not just any fibrations but the ones satisfying stack conditions, maybe these also have to be taken into account in determining Aut, I am not sure. | |
Apr 12, 2023 at 7:55 | comment | added | მამუკა ჯიბლაძე | Thanks, this is clearer to me now. Still, there is, I think, a subtlety there. On categorifying, properties turn into structures. So when you say $\operatorname{Aut}(\mathfrak P)$ is taken over Man, this actually means that objects of this category are pairs $(A,\alpha)$ where $A$ is an autoequivalence of $\mathfrak P$ and $\alpha$ is an isomorphism between $\pi_{\mathfrak P}$ and $\pi_{\mathfrak P}\circ A$, where $\pi_{\mathfrak P}$ is the fibration of $\mathfrak P$. Morphisms in Aut($\mathfrak P$) must respect those $\alpha$s. | |
Apr 12, 2023 at 7:36 | history | edited | Spai | CC BY-SA 4.0 |
added more details to the question after the suggestion given below.
|
Apr 12, 2023 at 7:34 | comment | added | Spai | The action is defined as a monoidal functor from the 2-group G to Aut($\mathfrak{P}$) where the automorphisms are over Man. So there is compatibility with that structure. Even the equivalence of categories is over Man. Let me add that clearly in the post. Let me think about the last point. | |
Apr 12, 2023 at 5:44 | comment | added | მამუკა ჯიბლაძე | Both $\mathfrak P$ and $\mathfrak X$ are not mere categories, they are both fibred over your site. Don't you need some condition about compatibility of the action with this structure? Also, you should somehow ensure that $\mathfrak X$ is actually equivalent, via $\pi$, to the quotient of $\mathfrak P$ by the action of $G$. | |
Apr 12, 2023 at 4:59 | history | asked | Spai | CC BY-SA 4.0 |