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Apr 7, 2023 at 15:49 comment added Chris Gerig I see, there are two pure strategies {([1,0], same), ([0,1], same)} and one mixed strategy ([e/(1+e),1/(1+e)], [same]), so that the latter two collide. How about pure strategies bifurcating/colliding with just pure? Is there any result of the form "any 2d dynamical system with discrete fixed points can be translated into a family of 2-player games with pure Pareto-optimal strategies"?
Apr 7, 2023 at 15:27 vote accept Chris Gerig
Apr 7, 2023 at 5:32 comment added Michael Greinecker Take a coordination game between players both having the purse strategies $L$ and $R$ available. The payoff is $0$ unless both choose the same action. Both get a payoff of $1$ if they choose $L$ and a payoff of $\epsilon$ if they both choose $R$. For $\epsilon>0$, there are three equilibria, for $\epsilon=0$, there are only two.
Apr 7, 2023 at 0:17 comment added Chris Gerig Is there an explicit/implicit example of a deformation of games where either: 1) a unique Nash equilibrium bifurcates into two, or 2) a finite set of Nash equilibria collide or die?
Apr 6, 2023 at 5:57 history answered Michael Greinecker CC BY-SA 4.0