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Apr 4, 2023 at 23:55 comment added Elías Guisado Villalgordo @nme okay, that explains it then, thx.
Apr 4, 2023 at 23:50 comment added mme Note that in this case $\delta \theta$ is the function $-*d*\theta$. When one says "integrate a function over M", they mean the n-form $fd\text{vol}_n = *f$. So the left-hand-side really means $\int -d*\theta$. The given statement is Stokes' theorem applied to the 1-form $*\theta$, except that (unless I have made a sign error) there is a missing minus sign somewhere.
Apr 4, 2023 at 23:34 history undeleted Elías Guisado Villalgordo
Apr 4, 2023 at 23:33 history deleted Elías Guisado Villalgordo via Vote
Apr 4, 2023 at 23:33 history asked Elías Guisado Villalgordo CC BY-SA 4.0