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Mar 29, 2023 at 15:14 vote accept BasicQuestionBot
Mar 29, 2023 at 8:40 answer added A Stasinski timeline score: 10
Mar 28, 2023 at 18:00 history edited BasicQuestionBot CC BY-SA 4.0
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Mar 28, 2023 at 17:44 answer added ahulpke timeline score: 8
Mar 28, 2023 at 15:00 comment added BasicQuestionBot @DavidESpeyer: That's a really nice way to think about it, thanks!
Mar 28, 2023 at 15:00 comment added BasicQuestionBot @YCor: Ah, that's a cool theorem I didn't know about! I guess it follows from the fact that the the $p$-primary part of group cohomology is supported on a $p$-Sylow subgroup.
Mar 28, 2023 at 13:55 comment added David E Speyer Regarding: "I don't have any deep explanation as to why this works". $\text{SL}_2(\mathbb{Z}/2 \mathbb{Z})$ is isomorphic to $S_3$, which has a $2$-dimensional representation over the integers. Unfortunately, that representation involves matrices with determinant $1$ .
Mar 28, 2023 at 13:34 answer added David E Speyer timeline score: 6
Mar 28, 2023 at 12:05 answer added YCor timeline score: 10
Mar 28, 2023 at 11:11 comment added YCor Ah, OK, in view of the given observations, for $n=2$ it only splits for $p=3$ (Gaschütz applies precisely iff the elementary matrix $e_{12}(1)$ lifts).
Mar 28, 2023 at 8:20 answer added Dave Benson timeline score: 17
Mar 28, 2023 at 7:07 comment added YCor @BasicQuestionBot Essentially copying as in math.ku.dk/~olsson/manus/Gruppe-2009/gruppe2007en_all.pdf, p16: let $p$ be a prime and let $M$ be a normal abelian $p$-subgroup of a finite group $G$. Then $M$ has a direct complement in $G$ if (and only if) it has a direct complement in some/any $p$-Sylow subgroup of $G$.
Mar 28, 2023 at 1:14 comment added BasicQuestionBot @YCor: Interesting, which theorem of Gaschütz are you thinking of?
Mar 28, 2023 at 1:13 comment added BasicQuestionBot @DavidESpeyer: Whoops, you're right! I'll have to go back and see if I can fix this.
Mar 28, 2023 at 1:09 comment added David E Speyer The splitting you give for $p=2$ give matrices with determinant $-1$.
Mar 28, 2023 at 1:09 comment added YCor @LSpice yes it splits for $(n,p)=(2,2),(2,3)$: by Gaschütz' theorem it's enough to do it on $p$-Sylows of the quotient, which are cyclic of order $p$, and indeed split.
Mar 28, 2023 at 1:02 history edited LSpice CC BY-SA 4.0
`SL` -> `\SL`
Mar 28, 2023 at 0:51 comment added BasicQuestionBot @LSpice: I added the answer I know there to the question.
Mar 28, 2023 at 0:50 history edited BasicQuestionBot CC BY-SA 4.0
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Mar 27, 2023 at 23:03 comment added LSpice Do you know the answer for $n = 2$?
Mar 27, 2023 at 22:06 review Close votes
Apr 1, 2023 at 3:11
Mar 27, 2023 at 21:41 history edited YCor CC BY-SA 4.0
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Mar 27, 2023 at 22:10
S Mar 27, 2023 at 21:14 history asked BasicQuestionBot CC BY-SA 4.0