Timeline for Vector measures as metric currents
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Mar 27, 2023 at 8:03 | history | bounty ended | CommunityBot | ||
| Mar 22, 2023 at 9:57 | comment | added | Jochen Wengenroth | Considering characteristic functions of nice sets as you suggest, the partial integration which is behind the distributional derivative yields boundary terms which I cannot handle. | |
| Mar 22, 2023 at 9:55 | comment | added | Jochen Wengenroth | Thanks for your answer. The argument for $f=1$ is correct but I don't see a way to extend it to the general case. Just by the product rule one gets $$\sum \int f\partial_j\pi_j\ d\mu_j = \int f\pi d\nu - \sum\int (\partial_j f)\pi\ d\mu_j$$ which leaves us in the same miserable situation as before. Put in a different way, $\sum \int f\partial_j\pi \ d\mu_j$ is (up to a minus sign) the distributional divergence of the measure $f\cdot\mu$ applied to $\pi$ but probably this divergence does not need to be again a measure. | |
| Mar 21, 2023 at 17:19 | history | answered | mlk | CC BY-SA 4.0 |