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Mar 20, 2023 at 15:18 comment added Jason Starr That is not a counterexample to the original post. The OP does not write that $Y’$ must be finite over $X$, merely birational to a finite morphism.
Mar 20, 2023 at 15:02 comment added user19232801 It seems that the reason for this counterexample is that $X$ has nontrivial line bundles. What happens if one replaces $X \times \mathbb A^1$ with $L$ for some line bundle $L$ over $X$?
Mar 20, 2023 at 12:50 history answered Roberto Pignatelli CC BY-SA 4.0