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Oct 30, 2010 at 23:52 comment added Deane Yang Justin, in your question, you say "I can extend the above definition of involutive distribution to this subbundle in the obvious way. Let me take this as a definition of integrable subbundle." So aren't you claiming that you do have a definition of an involutive or integrable distribution for a vector bundle?
Oct 30, 2010 at 22:22 comment added Dick Palais @Justin Curry: I don't believe so. Part of the reason is that it is not at all clear how to generalize the notion of integrability for an arbitrary vector bundle. (Actually, "worked out" is a somewhat misleading way of putting it: it makes it sound like there must be a natural generalization of those notions for subbundles of bundles more general than the tangent bundle, while what Deane Yang and I have been trying to say is that we do not believe this is so.)
Oct 30, 2010 at 21:01 comment added Justin Curry Ah, part of my question was whether the notion of integrable or involutive had been worked out for arbitrary vector bundles.
Oct 30, 2010 at 20:35 comment added Deane Yang In particular, it is not at all clear what "in the obvious way" means in the question. I suggest that the questioner try to work out the details of what "involutive" is supposed to mean for a vector bundle. As far as I know, there is no such concept.
Oct 30, 2010 at 20:12 history answered Dick Palais CC BY-SA 2.5