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Mar 13, 2023 at 19:41 vote accept anon.for
Mar 12, 2023 at 21:30 comment added Iosif Pinelis Your assertion that $J'(u)=2u(x)$ is wrong and actually makes no sense, for several reasons, including the following: (i) the $x$ there is undefined; (ii) $J'(u)$ is a linear functional, while $u(x)$ is a number (if $x$ is a point between $0$ and $l$); (iii) we can identify $J'(u)$, in a certain manner, with $2u$ only if $u$ is real valued. See the answer below for details.
Mar 12, 2023 at 21:22 answer added Iosif Pinelis timeline score: 3
Mar 12, 2023 at 20:45 history edited Daniele Tampieri CC BY-SA 4.0
Minor Math Jaxing + grammar improvement
S Mar 12, 2023 at 20:28 review First questions
Mar 12, 2023 at 22:57
S Mar 12, 2023 at 20:28 history asked anon.for CC BY-SA 4.0