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Mar 10, 2023 at 15:42 history edited Sean Eberhard CC BY-SA 4.0
small correction to Gillyweeds's correction
Mar 10, 2023 at 15:32 history rollback Sean Eberhard
Rollback to Revision 2
Mar 10, 2023 at 15:27 comment added Sean Eberhard @Gillyweeds The polynomial identity $\Delta^{p-1} = 1 + \sigma + \cdots + \sigma^{p-1}$ uses the fact that $G$ has exponent $p$.
S Mar 10, 2023 at 15:24 history edited Sean Eberhard CC BY-SA 4.0
I have checked with GAP which is the LCS of $C_{p^2}\wr C_p$.
S Mar 10, 2023 at 15:24 history suggested Gillyweeds CC BY-SA 4.0
I have checked with GAP which is the LCS of $C_{p^2}\wr C_p$.
Mar 10, 2023 at 14:06 review Suggested edits
S Mar 10, 2023 at 15:24
Mar 10, 2023 at 14:03 comment added Gillyweeds I have a small question. At the beginning where do you use that $G$ is elementary abelian? Is it to get that the map $\Delta$ has $\dim \ker\Delta= \dim G$?
Mar 8, 2023 at 18:18 vote accept Gillyweeds
S Mar 8, 2023 at 11:24 history suggested Gillyweeds CC BY-SA 4.0
I think that when you write "First consider the case in which $G$ is abelian" you actually mean elementary abelian.
Mar 8, 2023 at 11:07 review Suggested edits
S Mar 8, 2023 at 11:24
Mar 7, 2023 at 16:24 history answered Sean Eberhard CC BY-SA 4.0